feeding current output to current tick
Hiroko Shiraiwa-Terasawa
hiroko@ccrma.Stanford.EDU
Mon, 12 May 2003 16:56:30 -0700 (PDT)
> I've been looking at this, and don't see how it works...
> by definition the feedback should be delayed... ie it should come out
> only after you have made an output.. hence Y(n-1) <-> y * z^-1
> So what is the problem?
> Plus, "delay free" loops are impossible to implement in the digital domain.
feedback filters:
You have a delay at the direct path from x to y, but by definition, you
don't have delay at the feedback (recursive) path. the idea is to read one
sample ahead and provide it at the next turn.
--
Hiroko Terasawa
<hiroko@ccrma.stanford.edu>